Robbie Hatley's Solutions To The Weekly Challenge #237

For those not familiar with "The Weekly Challenge", it is a weekly programming puzzle, usually with two parts, cycling every Sunday. You can find it here:

The Weekly Challenge

This week (2023-10-01 through 2023-10-07) is weekly challenge #237.

Task 1 is as follows:

Task 1: Seize The Day
Submitted by: Mark Anderson
Given a year, a month, a weekday of month, and a day of week
(1 (Mon) .. 7 (Sun)), print the day.

Example 1:
Input: Year = 2024, Month = 4, Weekday of month = 3, day of week = 2
Output: 16
The 3rd Tue of Apr 2024 is the 16th

Example 2:
Input: Year = 2025, Month = 10, Weekday of month = 2, day of week = 4
Output: 9
The 2nd Thu of Oct 2025 is the 9th

Example 3:
Input: Year = 2026, Month = 8, Weekday of month = 5, day of week = 3
Output: 0
There isn't a 5th Wed in Aug 2026

I am soooooo not going to pull in all of the heavy artillery from my "day-of-week.pl" script; it's just not needed for this. I'll use "use Time::Local 'timelocal_modern';" and "localtime" instead, and I'll use this algorithm:

  1. Start with day-of-month set to zero, then enter this loop:
  2. Loop while dow-counter < weekday-of-month, else skip to step 9 below.
  3. Increment day-of-month.
  4. If day-of-month is now invalid, set it to 0 and exit loop.
  5. Get seconds-since-epoch for current day-of-month (using "timelocal_modern")
  6. Get current-day-of-week from seconds-since-epoch (using "localtime")
  7. Increment dow-counter if current dow == target dow.
  8. Loop back to step 2.
  9. Print results.

The script I came up with was this:

Robbie Hatley's Solution to The Weekly Challenge 237-1

Task 2 is as follows:

Task 2: Maximize Greatness
Submitted by: Mohammad S Anwar
You are given an array of integers. Write a script to permute the
given array such that you get the maximum possible "greatness".
To determine "greatness", nums[i] < perm[i] where 0 ≤ i < nums.length

Example 1:
Input: @nums = (1, 3, 5, 2, 1, 3, 1)
Output: 4
One possible permutation: (2, 5, 1, 3, 3, 1, 1) which returns
4 greatness as below:
nums[0] < perm[0]
nums[1] < perm[1]
nums[3] < perm[3]
nums[4] < perm[4]

Example 2:
Input: @ints = (1, 2, 3, 4)
Output: 3
One possible permutation: (2, 3, 4, 1) which returns
3 greatness as below:
nums[0] < perm[0]
nums[1] < perm[1]
nums[2] < perm[2]

I've no time to re-invent yet-another array-permutations subroutine this weekend so I'll use CPAN module "Math::Combinatorics", which has come to my aid in so many of these weekly challenges. Then it's just a matter of checking the "greatness" of every possible permutation of a given array and keeping track of "maximum greatness found so far".

The script I ended up with is this:

Robbie Hatley's Solution to The Weekly Challenge 237-2

That's it for 237; see you on 238!

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